Calculate the volume, in milliliters, of a 0.290 M LiOH solution that will completely neutralize each of the following:

Question

a. 40.0 mL of a 0.130 M H3PO4 solution
b. 24.5 mL of a 0.535 M H2SO4 solution

Answer 1

I will do one.

a) Normalityacid*volumeacid=Normalitybase*Vb

.130*3*40=.290*1*Vb
solve for volume base (LiOH)

note, Normality of an acid=Molarity*H+eqivalents

H+ equivalents of H3PO3 is 3
H+ equivalents of H2SO4 is 2