I would try this.
dGo = dHo - TdSo
Then dGo = -RTlnK and solve for Kp
Then Kp = pHg(g)
Calculate the vapor pressure of Hg at 14 oC (in atm).
Hg(l) ↔ Hg(g) . . . ΔHo = 61.32 kJ and ΔSo = 98.83 J/K
1 answer
Hg(l) ↔ Hg(g) . . . ΔHo = 61.32 kJ and ΔSo = 98.83 J/K
1 answer