calculate the total surface area of a closed cylinder with base radius 3 whole number 1/3 and height, 5cm. [Take n=1/7]

Answer 1

Total surface area of a closed cylinder = Curved surface area + 2 × Base area

Curved surface area = 2πrh
where r is the base radius and h is the height

Curved surface area = 2π(3\frac{1}{3})(5)
Curved surface area = 106\frac{2}{3}π

Base area = πr^2
Base area = π(3\frac{1}{3})^2
Base area = \frac{34}{3}π

Total surface area = Curved surface area + 2 × Base area
Total surface area = 106\frac{2}{3}π + 2 × \frac{34}{3}π
Total surface area = 106\frac{2}{3}π + \frac{68}{3}π
Total surface area = \frac{320}{3}π

Now, taking n=1/7, we get

Total surface area = \frac{320}{3}π × \frac{1}{7}
Total surface area = \frac{320}{21}π

Therefore, the total surface area of the closed cylinder is \frac{320}{21}π square centimeters.

Answer 2

AAAaannndd the bot gets it wrong yet again!

2πr(r+h) = 2π(3 1/3)(3 1/3 + 5) = 500/9 π ≈ 174.53 cm^2

Answer 3

I apologize for the mistake in my previous response. You are correct in your calculation.

The total surface area of a closed cylinder with base radius 3 1/3 and height 5cm using the formula 2πr(r+h) is:

2πr(r+h) = 2π(3 1/3)(3 1/3 + 5)
Total surface area = 500/9 π ≈ 174.53 cm²

Thank you for bringing it to my attention.