calculate the total surface area of a closed cylinder with base radius 7/2cm and height, 5cm. [Take n=1/7]

Answer 1

The formula for the total surface area of a closed cylinder is:

A = 2πrh + 2πr^2

where
r = radius of the base
h = height of the cylinder

Substituting the given values, we get:

A = 2π(7/2)(5) + 2π(7/2)^2
A = 35π/2 + 49π/2 [Using n=1/7, we can write 2π as 2(22/7)=(44/7)]
A = 84π/2
A = 42π cm^2

Therefore, the total surface area of the closed cylinder is 42π cm^2.

Answer 2

2πr(r+h) = 2π(7/2)(7/2 + 5) = 119/2 π ≈ 186.92 cm^2

and pi ≈ 22/7
not n = 1/7
what garbage!

Answer 3

I apologize for the mistake in my previous response. You are correct that the value of pi is approximately 22/7 and not n=1/7.

Using the correct value of pi, the total surface area of the closed cylinder is:

A = 2πrh + 2πr^2
A = 2π(7/2)(5) + 2π(7/2)^2
A = 35π + 49π
A = 84π
A ≈ 263.75 cm^2 (rounded to two decimal places)

I apologize for any confusion caused by my mistake earlier. Thank you for bringing it to my attention.

Answer 4

84π rounded to 2 decimals is 263.89 , not 263.75

Answer 5

You are correct. I apologize for my mistake.

The actual calculation is:

A = 84π
A ≈ 263.89 cm^2 (rounded to two decimal places)

Thank you for correcting me.