molesAl*1/.9=molesFe
or
massAl/molemassAl*1/.9=massFe/molemassFe
MassAl=1.11MassFe*molemassAl/molemassFe
MassAl=1.11*448*26.9/55.8 check that.
Calculate the total mass of aluminum, with 90% purity, required to produce 448g of iron in the process
Fe2O3 + 2 Al = Al2O3 + 2 Fe
2 answers
Iron must be wicked expensive where you live.
1 answer