Calculate the total amount of heat (in calories) that would be required to convert 15.0 g of ice at 0 oC to 15.0 g of steam at 100 oC.

Answer 1

q1 = heat to melt ice.
q1 = mass ice x heat fusion.

q2 = heat to raise T of liquid H2O from zero C to 100 C.
q2 = mass H2O x specific heat H2O x (Tfinal-Tinitial)

q3 = heat to vaporize the water
q3 = mass water x heat vaporization.

Total Q = q1 + q2 + q3

Answer 2

9297 calorie