add the heat of fusion, heat of heating, and the heat of vaporization:
heat=2 *80+2 *1*100+ 2*540
= 160+200+1080
add them up
What is the heat required in kilocalories to convert 2 kg of ice at 0°C completely into steam at 100°C?
-80 Calories
-1440 Calories
-4186 Calories
-540 Calories
Thanks!
2 answers
Thanks this answer is very useful and easy to understand