calculate the theoretical number of moles of HCl equivalent to 1 mole of
a) NaHCO3
b)CaCO3
c)Al2O3
5 answers
Write out the equations and tell me what you think.
a)HCl + NaHCO3 -> NaCl + H2O + CO2
b)2HCl + CaCO3 -> CaCl2 + H2CO3
-> CaCl2 + H2O + CO2
c) Al2O3 + HCl -> AlCl3 + H2O + O2
hmmm
a) 1mole
b) 2moles
3) 1
??
b)2HCl + CaCO3 -> CaCl2 + H2CO3
-> CaCl2 + H2O + CO2
c) Al2O3 + HCl -> AlCl3 + H2O + O2
hmmm
a) 1mole
b) 2moles
3) 1
??
oh! is it right? i need to multiply the number of HCl to 1mol/6.022x10^(23)?
a)HCl + NaHCO3 -> NaCl + H2O + CO2
This is fine
b)2HCl + CaCO3 -> CaCl2 + H2CO3
-> CaCl2 + H2O + CO2
OK also
c) Al2O3 + HCl -> AlCl3 + H2O + O2
very few reactions yield O2
3HCl + Al2O3 ---> 2AlCl3 + 3H2O
a) 1 mole - agreed
b) 2 moles - agreed
3) here 3 moles
This is fine
b)2HCl + CaCO3 -> CaCl2 + H2CO3
-> CaCl2 + H2O + CO2
OK also
c) Al2O3 + HCl -> AlCl3 + H2O + O2
very few reactions yield O2
3HCl + Al2O3 ---> 2AlCl3 + 3H2O
a) 1 mole - agreed
b) 2 moles - agreed
3) here 3 moles
thank you. i'm just confused what to use to find the number of moles, when there's mass and other given.
thanks for the help.
thanks for the help.