Kinetic Energy = 1/2 times m v^2
1.00 x 10^-19 = (1/2)(1.673x10^-27)v^2
solve for v^2 then take the square root to get v.
Calculate the speed of a proton having a kinetic energy of 1.00 × 10^−19
J and a mass of 1.673 × 10^−27kg.
Answer in units of m/s
2 answers
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