Calculate the Riemann sum of the area under the curve of f(x)=9-x^2 between x=-2 and x=3

The answer I come up with is 10/3, but when I solve using integrals, the answer I get is 100/3. Am I doing something wrong?

1 answer

looks like a decimal place error, check that.

Here is what Worlfram says:
http://www.wolframalpha.com/input/?i=riemann+sum+9-x%5E2+between+x%3D-2+and+x%3D3
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