Calculate the ratio of NaF to HF required to create a buffer with pH=3.95.
Also, can you please explain in a nutshell the whole concept of buffers?
Thanks!
6 answers
Never mind, I figured it out.
what was the anwer?
pH=pKa + log(base/acid)
3.95=3.465 + log(base/acid)
.494=log(base/acid)
10^.494
3.1
3.95=3.465 + log(base/acid)
.494=log(base/acid)
10^.494
3.1
thanks!!
wait what? that's not right the -log(.494) = 2.02
john the answer is right 3.1; u have to key on ur calc 2nd key then log key then the (^)key :) to get that answer.
1 answer