Calculate the ppm of the sodium ions when 2.91 g of sodium triphosphate are added to 2.33 L of solution.

Question

I earnestly have no idea how to solve this...

Answer 1

One factor worth remembering is 1 ppm = 1 mg/L.
Convert 2.91g Na3PO4 to g Na. That is
2.91 g Na3PO4 x (3*atomic mass Na/molar mass Na3PO4) = ?. You have ? g Na^+ in 2.33 L.
That is (? g Na^+/2.33 L solution) = ? g Na/L; now convert ?g/L to ?mg/L.