calculate the PH of [OH-]

Question

= 4.5×10−3 M

Please show how you work this problem.

Answer 1

pOH = -log(OH^-)
pOH = -log(4.5E-3)
Then pH + pOH = pKw = 14 so
pH = 14-pOH
You should end up with 11.65

Answer 2

thank you