I think you need only one ICE table.
........HF + OH^- ==> F^- + H2O
I.....0.75...0.......0.25......
add.........0.05.............
C....-0.05.-0.05......+0.05
E.....0.70....0........0.30
Substitute the E line into the HH equation and solve for pH.
Calculate the pH of a buffered solution prepared from 0.25 mol KF and 0.75 HF after the addition of 0.05 mol of NaOH (assume a 1.0 L volume of solution)
I get that i need to use two separate ice tables, but i don't really understand how to go about doing that?
1 answer
1 answer