Calculate the ph of a 1L solution to wgich has been added 25ml of 10mM acetic acid and 25ml of 30mM sodium acetate

Answer 1

acetic acid = HAc
sodium acetate = NaAc
The way I interpret the problem as to how the author wants it solved is that you have 1L of solution containing 25 mM HAc and 30 mM NaAc; however, technically that isn't what it says to me.
(HAc) = 0.01 M x (25/1000) = ?
(NaAc) =0.03 M x (25/1000) = ?

Then pH = pKa for HAc + [log(NaAc)/(HAc)]
Post your work if you get stuck.