Assuming the density of a 5% acetic acid solution is 1g/ml, determine the volume of the acetic acid solution necessary to neutralize 25ml of 0.1m naoh also record this calculation on your report
My calculation
1g/ml x 1000ml x 0.05/61 = 0.81M
0.81m = 25ml x 0.1
0.81m = 2.5
x= 2.5/0.81
x= 3ml
or 25ml x .01m = 2.5ml x 61 /0.05/ 1
x 3ml
Who helps me to solve it for me