Calculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH.
The Ka for HOCl is 3.0 x 10-8 M.
What is the pH at the equivalence point?
I used the HH formula and got pH=7.52+log(.222)=6.87, but its not right.
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