CALCULATE THE pH AND HYDROLYSIS IN 0.10 M AlCl3 SOLUTION.Ka = 1.2 X 10-5 FOR [Al(OH2)6]+3,OFTEN ABBREVIATED Al+3.TELL WHETHER pH IS ACID OR BASE.GIVE IONIC EQUATION.

Help us a little by telling us how much you know to do and exactly what you don't understand about the problem. Then we can help you through it.

i don't understand how to solve it.

I really wanted more help than that. I know you can't solve it; if you could, you wouldn't have asked for help. I wanted to know WHAT about the problem you don't understand. Here are some hints to get you started.
[Al(H2O)6]3+ + H20 ==> [Al(H2O)5(OH)]2+ + H3O+

Write the Ka expression. If you let x = H3O^+, then the other product = x also, and the problem tells you that the starting material is 0.1 M. Plug in those values, solve for x and convert that to pH.
Post your work if you get stuck.

1 answer

pH IS 2.96