Calculate the molarity (M) of AlCl3 in a solution prepared by adding 0.750 L of 0.7 M AlCl3 and 0.250 L of 0.1 M AlCl3 . Assume volumes are additive

2 answers

total moles: .7*.750+.250*.1

total volume= 1liter

Molalrity= total moles/1
0.9