Calculate the pH after 0.016 mole of NaOH is added to 1.05 L of a solution consisting of 0.138 M HONH2 and 0.127 M HONH3Cl, and calculate the pH after 0.016 mole of HCl is added to 1.05 L of the same solution of HONH2 and HONH3Cl. (Assume that all solutions are at 25°C.)
0.016 mole of NaOH
0.016 mole of HCl
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