Question

Calculate the partial pressure of monatomic hydrogen in hydrogen gas at 2000 K and 1 atm pressure.

Given:
(i) For ½ H2 ï‚® H, Ho298=217,990 J; So298=49.35 J/K.
(ii) Assume that the heat capacity of monatomic gas to be 3/2R
(iii)The heat capacity of H2 assume to be 31 J/(mol K)

Answer 1

For 1/2 H2 -> H, DeltaHo298=217,990 J; DeltaSo298=49.35 J/K

Nb: DeltaHo298=DeltaH standard at 298K
DeltaSo298=DeltaS standard at 298K

Guys, pliz help me, I need to get general ideas of how to do this.
thank you so much.

Answer 2

Do we have to find deltaH and deltaS at 2000K, and after that , find deltaG by using this formula deltaG=deltaH-T*deltaS
.
Next, deltaG=-RT*lnKp
where Kp=P(H)/((p(h2))^(1/2))
If this is correct, what is p(h2)/ partial pressure of hydrogen? so that we can find partial pressure for the monatomic hydrogen?

Answer 3

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-mats-