2Al(s) +3FeO = 3Fe(s) + Al2O3(s)
The coefficients tell you.
0.6 mol Fe x (1 mol Al2O3/3 mol Fe) = 0.6 x 1/3 = ?
calculate the number of moles of Al2O3 that are produced when .60 mol of Fe is produced in the following reaction. 2Al(s) +3FeO = 3Fe(s) + Al2O3(s)
1 answer