Calculate the molarity of 0.205 L of a solution that contains 156.5 g of sucrose

Answer 1

To calculate the molarity of a solution, we first need to calculate the number of moles of the solute (in this case, sucrose) present in the solution.

The molar mass of sucrose (C12H22O11) is approximately 342.3 g/mol.

Number of moles of sucrose = 156.5 g / 342.3 g/mol = 0.457 moles

Now, we need to calculate the molarity of the solution using the formula:

Molarity (M) = Number of moles of solute / Volume of solution in liters

Molarity = 0.457 moles / 0.205 L = 2.23 M

Therefore, the molarity of the solution is 2.23 M.