Calculate the mass of water produced when 3.94 g of butane reacts with excess oxygen.

Question

Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown in the following chemical equation:
2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)

Answer 1

2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g)
mols C4H10 = 3.94/molar mass = ?
For every 2 mols C4H10 you get 10 mol H2O; therefore, mols H2O = ?
Convert mols H2O to grams. g = mols x molar mass = ?
Post your work if you get stuck.