2C4H10 + 13O2 --> 8CO2 + 10 H2O
mols C4H10 = g/molar mass = 3.64 g/58 = approx 0.063 but you need to redo all of these calculations.
Convert to mols H2O. That's
0.063 mols C4H10 x (10 mols H2O/2 mols C4H10) = 0.31 mols H2O.
Then grams H2O = mols H2O x molar mass H2O = ?
Post your work if you get stuck.
Calculate the mass of water produced when 3.64 g
of butane reacts with excess oxygen.
1 answer