calculate the mass of silver deposited when a current of 3ampere is passed through a solution of a silver salt for 7minutes

Answer 1

coulombs = amperes x seconds
C = 3A x 7 min x 60 sec/min = ?
96,485 coulombs will deposit 107.9 g Ag. So
107.9 g Ag x (? C/96,500 C) = ?