Calculate the mass of silver deposited when a current of 2.2A is passed through a solution of silver salt for 80 minutes.(Ag=108,1 farasay=96500c)
2 answers
Please help me solve it
Coulombs = amperes x seconds
C = 2.2 A x 80 minutes x (60 sec/min) = 10,560
You know that 108 g Ag will be deposited with 96,500 Coulombs and you have 10,560 so
108 g Ag x (10, 560/96,500) = ? g Ag
C = 2.2 A x 80 minutes x (60 sec/min) = 10,560
You know that 108 g Ag will be deposited with 96,500 Coulombs and you have 10,560 so
108 g Ag x (10, 560/96,500) = ? g Ag
4 answers