Calculate the mass of silver deposited when 0.2A of electricity is passed through a silver chloride solution for 2 hours, given that the chemical equivalence of silver is 0.000098g/c

Answer 1

I have a problem with the chemical equivalency given for Ag. Forgetting that for the moment:
If this is pure AgCl, then 96,485 coulombs will deposit 107.88 g Ag,
Coulombs = amperes x seconds = 0.2 A x 2 hr x (60 min/hr)(60 sec/min) = 1440.
107.88 g Ag x (1,440/96,485) = ? g Ag deposited.
I don't know where the value 0.000098g/c comes from. Perhaps the AgCl is not pure. Explain if you have further questions.