Calculate the linear expansivity of brass of length of 120m that assume a new length of 120.05m when heated through a temperature of 100°

Answer 1

change in length / length = k * change in temp
0.05 / 120 = k * 100
k = 0.0005/10 = 5 * 10^-4 / 10 = 5 * 10^-5

Answer 2

whoops, division wrong
0.05 / 120 = k * 100
= 0.05/12000 = 4.17 * 10^-6