Calculate the heat released when 73.5 g of steam at 122.0 C is converted to water at 39.0C. Assume that the specific heat of water is 4.184 J/g C, the specific heat of steam is 1.99 J/g C, and change in heat vap =40.79 kJ/mol for water.

Answer 1

q1 = heat released when steam @ 122 moves to 100.
q1 = mass steam x sp h steam x (Tfinal-Tinital)

q2 = heat released when steam condenses.
q2 = mass steam x heat vap

q3 = heat released when H2O @ 100 moves to 39 C.
q3 = mass H2O x sp h H2O x (Tfinal-Tinitial)

Then add q1 + q2 + q3.