Calculate the heat released when 64.5g of steam at 119 C is converted to water at 36 C. Assume the specific heat is 4.184 J/g*C for water, the specific heat of steam is 1.99J/g*C, and the heat of vaporization is 40.79 kJ/mol for water.

Answer 1

q1 = heat removed to lower T from 119 degrees C vapor to 100 degrees C vapor.
q1 = mass steam x specific heat steam x (Tfinal-Tinitial).

q2 = heat removed to condense steam at 100 C to liquid water at 100 C.
q2 = mass steam x heat vaporization.

q3 = heat removed to lower T from 100 C to 36 C.
q3 = mass water x specific heat water x (Tfinal-Tinitial).

Total Q = q1 + q2 + q3.