q1 = heat released when steam @ 100 C condenses to liquid water.
q1 = 10.7 g x 2260 J/g = ?
q2 = heat released when water @ 100 C is cooled to 37 C.
q2 = 10.7 g x 4.18 J/g*c x (Tfinal-Tinitial) = ? J where Ti is 100 and Tf is 100 C.
Total q is q1 + q2
Post your work if you get stuck.
A patient arrives in the emergency room with a burn caused by steam. Calculate the heat that is released when 10.7 g of steam at 100. ∘C hits the skin, condenses, and cools to body temperature of 37.0 ∘C. (For water, 540 cal (2260 J) is needed to convert 1 g of water to vapor at 100 ∘C.)
Express the heat to three significant figures and include the appropriate units.
4 answers
@DrBob222..
I still need help with that. I need help solving it by step by step
I still need help with that. I need help solving it by step by step
q1 = 10.7 g x 2260 J/g = ?
q2 = 10.7 g x 4.18 J/g*c x (Tfinal-Tinitial) = ? J where Ti is 100 and Tf is 100 C.
You still need help? Are you telling me that you can't multiply 10.7 x 2200 and come up with q1.
I made a typo on q2. It should be Tf = 37 and Ti = 100
Are you saying you cant solve q2 = 10.7 x 4.18 x (37 - 100)
q2 = 10.7 g x 4.18 J/g*c x (Tfinal-Tinitial) = ? J where Ti is 100 and Tf is 100 C.
You still need help? Are you telling me that you can't multiply 10.7 x 2200 and come up with q1.
I made a typo on q2. It should be Tf = 37 and Ti = 100
Are you saying you cant solve q2 = 10.7 x 4.18 x (37 - 100)
Hint: Try to recall that condensation is the route by which water vapor in the air is changed into liquid water. … It is known to you that for any substance, the condensation point is the same as the boiling point and the boiling point of water is 100 degree Celsius.