If he jumps unassisted (unlike pole vault), his air-borne time is dictated by the acceleration due to gravity, and is equal to twice the time t(for both up and down) for an object to free-fall through h metres.
h = (1/2)gt²
t=√(2h/g)
For h=0.75m
t=√(2*0.75/9.81)
=0.39s
2t = 0.78 s.
Calculate the hang time of an athlete who jumps a vertical distance of 0.75 meter.
2 answers
Calculate the hang time of an athlete who jumps a vertical distance of 0.75 meter
1 answer