Ask a New Question

calculate the freezing point of an aqueous solution of 15.5 grams of glucose dissolved in 150 grams of water

1 answer

mols glucose = grams/molar mass = ?
Then m = mols glucose/kg solvent
Then delta T = Kf*m
New freezing point = zero C - delta T.

Ask a New Question or answer this question.

Similar Questions

A 5.00-gram sample of glucose, C6H12O6, [molar mass = 180.] is dissolved 10.0 grams of waterWhat is the molality of the glucose
1. 1 answer
Calculate the new freezing point and the new boiling point of an aqueous solution that contains 40.5 g of Calcium Nitrate
1. 0 answers
A solution. Of glucose was prepared by dissolving certain amount in 100 grams of water ,the depression in freezing point is.
1. 1 answer
What are the freezing point and boiling point of an aqueous solution of 15.5 g glucose(C6H12O6) dissolved in 150 g of water?
1. 1 answer

more similar questions