Calculate the force required to move a small pistons that has an area of 2m2,if the force of a large piston is 20n with an as area of 4m2.Hint use a formulae :a frorce of small piston divided by an area of small piston equal to force of large pistone divided by area of large pistone

Answer 1

I assume you have the two pistons linked by a hydraulic liquid, in which case the hydraulic pressures are equal in both pistons.

Force/area=pressure, so
F1/A1=F2/A2
Here,
A1=2 m²
A2=4 m²
F2=20 N
so
F1=(F2/A2)*A1
=20/4*2 N
=10 N

The ratio (A2/A1) is called the mechanical advantage, which is the ratio of force reduction between the two pistons.

Also, note that the unit newton is written in all lower-case when written in full, and written in upper-case (N) when it is a symbol, same with other units which are derived from names of people, like (ampère, A), (faraday, F), ... etc.
Notable exceptions,
L is written in US in upper-case to avoid confusion with the digit 1. Sometimes it is written in lower-case script (with a loop) for the same reason.
1 Calorie = 1000 calories, where the case changes by a factor of a thousand.

Answer 2

Can I ask how did you get 10N ?

F1=(F2/A2) *A1
=20/4*2N
=10N
So can you please explain how you got the 10N

Answer 3

How did you get the answer 10 N after = 20\4*2N
It really isn't making sense

Answer 4

How did you get the 10N