Question

In a hydraulic system a 20.0-N force is applied to the small piston with cross sectional
area 25.0 cm2. What weight can be lifted by the large piston with cross sectional
area 50.0 cm2?

Would I need to divide both pistons areas then mutiply the force? and or have gravity in there somewhere since its weight?

Answer 1

No need for gravity.

F1/Area1 = F2/AREA2

Solver for F1

Answer 2

So it would be 50.0/25.0*20.0=40

Answer 3

20/25 = F/50

F = (20/25)*50

F= 40 N

Answer 4

thank you