Asked by justin
The small piston of a hydraulic lift has a
cross-sectional area of 3.6 cm2
and the large
piston has an area of 86 cm2.
What force F must be applied to the small
piston to maintain the load of 52 kN at a
constant elevation?
cross-sectional area of 3.6 cm2
and the large
piston has an area of 86 cm2.
What force F must be applied to the small
piston to maintain the load of 52 kN at a
constant elevation?
Answers
Answered by
shane
750 N
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