Asked by Elisabeth
the small piston of a hydraulic press has an area of 2.0 cm and the large piston has an area of 16 cm if the small piston has a force of 4.0 N applied to it the output force of the large piston is
Answers
Answered by
Damon
pressure = 4 N/2 cm^2 = 2 N/cm^2
force = pressure * area = 2 N/cm^2 * 16 cm^2
= 32 N
NOW area is cm^2 , not cm
cm is distance along a line
cm^2 is area of a surface
force = pressure * area = 2 N/cm^2 * 16 cm^2
= 32 N
NOW area is cm^2 , not cm
cm is distance along a line
cm^2 is area of a surface
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