Asked by dave

Calculate the equilibrium constant for the following reaction at room temperature, 25 ∘C:

N2(g)+O2(g)→2NO(g)
Answered by DrBob222
How, by guessing. There is no data.
Answered by dave
delta Gf for NO(g) is 87.6 kJ/mol
delta Gf for both O2 and N2 gas is zero

Answered by dave
Delta Gf= -RT*ln(K)
R is 8.314
T is 298
Answered by dave
Running through I got the answer 1.97x10^-31 but it is telling me I am wrong.
Answered by bobpursley
e^(-87600/(8.314*298))= = 4.41128049e-16

check that, I had to use google as a calculator.
Answered by DrBob222
I get 2*87.6*1000 = ? and
-?/8.314*298 = about -70 so
K = about 10^-70 or so. The number I obtained is 1.93E-71.
Answered by DrBob222
I just thought (about 10 hours after I posted this) I used log K and not ln K.
There are no AI answers yet. The ability to request AI answers is coming soon!