At what temperature is the value of
T delta S^0 equal to -16.7774 KJ/mol.?
I believe you mean SO2 as the second product on the right.
Once you know T, you can set the difference of the standard entropies of the reactants and products equal to the delta S of the reaction, and solve for the entropy of formation of CS2(l)
Calculate the entropy of formation (J/K mol) of CS2(l). The value of T delta S^0 for the equation as written is -16.7774 KJ/mol. (the given standard entropies are: O2= 205.138, CO2= 213.7, SO2= 248.22)
CS2(l) + 3 O2(g) --> CO2(g) + 2 O2(g)
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