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A reaction has deltaHrxn=-127 kJ and delta S rxn=314 J/K. At what temperature is the change in entropy for the reaction equal to the change in entropy for the surroundings?

so I made delta H-T delta S=0
plugged in values for S and H and solved for T. I got -404.5 degrees K.

Is this correct ?

2 answers

It can't be correct because there is no temperature that low.

Are you sure the two numbers had opposite signs?
no
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