Asked by Jessica
calculate the energy required to heat 1.00L of ice at -50.0C to steam at 180.0C
Answers
Answered by
DrBob222
q1 = heat to raise T of ice at -50C to zero C/
q1 = mass ice x specific heat ice x (50)
q2 = heat to melt the ice at zero to liquid at zero C.
q2 = mass ice x heat fusion.
q3 = heat to raise T of water at zero C to 100 C.
q3 = mass water x specific heat water x 100
q4 = heat to vaporize water at 100 C to steam at 100 C
q4 = mass water x heat vaporization
q5 = heat to raise T of steam at 100 C to steam at 180 C.
q5 = mass steam x specific heat steam x80
Total Q = q1 + q2+ q3 + q4 + q5
q1 = mass ice x specific heat ice x (50)
q2 = heat to melt the ice at zero to liquid at zero C.
q2 = mass ice x heat fusion.
q3 = heat to raise T of water at zero C to 100 C.
q3 = mass water x specific heat water x 100
q4 = heat to vaporize water at 100 C to steam at 100 C
q4 = mass water x heat vaporization
q5 = heat to raise T of steam at 100 C to steam at 180 C.
q5 = mass steam x specific heat steam x80
Total Q = q1 + q2+ q3 + q4 + q5
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