Question
A 500kg steel boiler is used to convert 200kg of water into steam. Calculate the total energy required to heat both the steel and its' contents from 20.0°C to 100.0°C. The specific heat capacity of the steel is 0.528J/g°C.
Heattotal= heat steel + heat water + heatsteam
= masssteel*Cs*(Tf-Ti) + mw*cw*(tf-ti)+ mw*Lv where Lv is the latent heat of vaporization for water
Heattotal= heat steel + heat water + heatsteam
= masssteel*Cs*(Tf-Ti) + mw*cw*(tf-ti)+ mw*Lv where Lv is the latent heat of vaporization for water
Answers
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