n1 = 1 and 1^2 = 1
n2 = 6 and 6^2 = 36
E = 2.18E-18J x (1/n1^2 - 1/n2^2)
E = 2.18E-18 J x (1/1 - 1/36)
Solve for E.
Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n = 6 to n = 1.
5 answers
for both? and then add them?
No. E = 2.18E-18J x (1/1 - 1/36) =
E = 2.18E-18J x (1-0.0278) = ?
I just wrote the formula and substituted so you could see where the numbers came from.
E = 2.18E-18J x (1-0.0278) = ?
I just wrote the formula and substituted so you could see where the numbers came from.
Where the hell did you get 2.18x10^-18 from
@drbob222 shes right thoooo
1 answer