Asked by ariel

Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n=5 to n=1 in J.

Answers

Answered by DrBob222
dE = 2.180E-18[1/(n1)^2 - (1/(n2)^2]

n1 = 1 and 1^2 = 1
n2 = 5 and 5^2 = 25
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