Calculate the electrical voltage of an electrochemical cell using Pb(s) and

Question

Co(s) as electrodes along with their appropriate solutions.

Co2+(aq) + 2e- --> Co(s) -0.28 V

Pb2+(aq) + 2e- --> Pb(s) -0.13 V

The oxidation reaction is

Co(s) --> Co2+(aq) + 2e- +0.28V

E0 net(cell) = E0 ox + E0 red
= (0.28 V) + (-0.13 V)
= +0.15 V

Does this look right? I am not sure if I answered what the question is asking.

Answer 1

Yes, that look fine to me. And your calculations are above reproach.