Calculate the efficiency of a machine with velocity ratio of 5 if a load of 100N is to be lifted by an effort of 50N

Answer 1

should take 100 / 5 = 20 N
actually takes 50 N
so if you move your hand one meter work done (input) = 50 * 1 = 50 Joules
ideal work done (output)= 20 * 1 = 20 Joules
eff = 100 * output work / input work = 100 * 20/50 = 40%

Answer 2

To solve