1. W = F*d = 400*10 = 4,000 J.
e = 4000/(4000+100) = 0.98 = 98 %.
2. e = L/E*Vr
0.98 = 400/5E
E = 82 N.
A block and tackle having a velocity ratio of 5 is used to raise a load of 400N through a distance of 10m. If the work done against friction is 100J. Calculate
1. Efficiency of the machine
2. The effort applied
4 answers
Can you please explain the answer 2.well for me .
Thank you
I don't understand