velocity ratio of 5 implies a distance ratio of 5
5 * 0.40 m = 2 m
work done by arms = 60*2 = 120 Joules
work done by lift on mass = 25*9.81*0.20
= 49.05 Joules
loss in energy = 120 - 49 = 71 Joules
Draw a block and tackle system of pulleys with a velocity ratio of 5.A block and tackle with a velocity ratio of 5 is used to raise a mass of 25kg through a vertical distanceof 40cm at a steady rate. If the efforts is equal to 60N, determine
a)d distance moved by the effort
b)the work done by the effort in lifting the load
c)the loss in energy involved in lifting the load.
3 answers
how do you get Your question b answer
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