calculate the density of a gold ring that has a mass of 15.83 grams and a volume of 0.82 milliliters.

3 answers

To calculate the density of the gold ring, you can use the formula for density:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

In this case, the mass of the gold ring is 15.83 grams and the volume is 0.82 milliliters. Plugging in these values:

\[ \text{Density} = \frac{15.83 , \text{grams}}{0.82 , \text{milliliters}} \approx 19.29 , \text{grams per milliliter} \]

Therefore, the density of the gold ring is approximately 19.29 grams per milliliter.

now calculate the density of a gold bar that has a mass of 1,000 grams and a volume of 51.8 milliliters. use the same formula for density

To calculate the density of the gold bar, we can use the same density formula:

\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]

Given that the mass of the gold bar is 1,000 grams and the volume is 51.8 milliliters, we can substitute these values into the formula:

\[ \text{Density} = \frac{1,000 , \text{grams}}{51.8 , \text{milliliters}} \approx 19.31 , \text{grams per milliliter} \]

Therefore, the density of the gold bar is approximately 19.31 grams per milliliter.